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x^2+6x+0.33x+2=0
We add all the numbers together, and all the variables
x^2+6.33x+2=0
a = 1; b = 6.33; c = +2;
Δ = b2-4ac
Δ = 6.332-4·1·2
Δ = 32.0689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.33)-\sqrt{32.0689}}{2*1}=\frac{-6.33-\sqrt{32.0689}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.33)+\sqrt{32.0689}}{2*1}=\frac{-6.33+\sqrt{32.0689}}{2} $
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